=lim (x-2)/((x-2)(x+2)) (当x趋近于2时， sin(x-2)与x-2是等价无穷小)
=lim 1/x+2
=1/4（代入x=2得）
lim(x→2)x-2 \/sin( x2-4)详细过程
=limx->2 (x^2-4)\/[(x+2)sin(x^2-4)]因为x->2,所以limx->2 x^2-4=0 所以limx->2 (x^2-4)\/sin(x^2-4)=1 原式 =limx->2 1\/(x+2)=1\/4
计算题 lim(x→2)x-2分之sin(x方-4)
=lim (x+2)sin(x²-4)\/[(x+2)(x-2)]x→2 =lim (x+2)sin(x²-4)\/(x²-4)x→2 =(2+2)·1 =4
limx→2(x^2-4)\/sin(x-2),求极限
limx→2(x^2-4)\/sin(x-2)=limx→2(x+2)[(x-2)\/sin(x-2)],当x→2时,x-2→0,x+2→4,故x→2时,有(x-2)\/sin(x-2)→1.原式=4
求解lim x→2 x^2-4\/sin(x-2),要过程,谢
当x→2时，x＾2-4→0；sin(x-2)→0，对分子分母进行求导。即lim x→2 x＾2-4\/sin(x-2)=lim(x＾2-4)'\/[sin(x-2)]'=lim2x\/cos(x-2)=lim2*2\/1=4 所以lim x→2 x＾2-4\/sin(x-2)=4
计算极限limx->2 x的平方-x-2\/x的平方-4
lim(x->2) (x^2-x-2)\/(x^2-4)=lim(x->2)(x+1)\/(x+2)=3\/4
limx→2(x^2-4)\/sin(x-2),求极限
limx→2(x^2-4)\/sin(x-2)=limx→2(x+2)[(x-2)\/sin(x-2)],当x→2时,x-2→0,x+2→4,故x→2时,有(x-2)\/sin(x-2)→1.原式=4
limsinx2-4\/sin(x-2)(x-2) 求极限
当x趋于2时,limsin(x^2-4)\/sin（x-2)^2=lim{(x^2-4)sin(x^2-4)\/(x^2-4)*(x-2)^2\/sin(x-2)^2(x-2)^2 =lim（x^2-4)\/(x-2)^2=无穷大
limx→2 x²+2x³\/(x-2)³计算极限?
直接代入法，分子当X→2时不为0，分母x→2时，分母趋近于0，所以极限不存在，即极限=∞。
求极限lim(x→2)(x^2-4)sin1\/(x-2),求详细过程～
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