=1/2,
(tan x-sin x)/ï¼x²Â·sin xï¼
=sinx(1/cosx-1)/ï¼x²Â·sin xï¼
=(1-cosx)/x²Â·cosx
cosx=1
1-cosx=1/2x²Â·
=1/2
(tan x-sin x)/ï¼x²Â·sin xï¼
=sinx(1/cosx-1)/ï¼x²Â·sin xï¼
=(1-cosx)/x²Â·cosx
cosx=1
1-cosx=1/2x²Â·
=1/2
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