两道英文数学题 求具体步骤

Question

(a) Find the shortest distance from the circle C x^2+y^2-6x+2y-6=0 to the line .
x+y=14
(b) Find the equation of the line which passes through (0,3) and which is tangent to the circle C in (a).

Answer 1

（a）找到圆C：x^2+y^2-6x+2y-6=0 到直线x+y=14的最短距离；

（b）找出穿过点(0,3)并与（a）中圆C相切的直线。

题目简单了，自己做吧