1\/4+1\/12+1\/24+1\/40+……+1\/19800 求详细解题过程!!!
解:原式1\/4+1\/12+1\/24+1\/40+……1\/19800=1\/4+1\/12+1\/24+1\/40+……+1\/19800 =(1\/2)*[1\/2+1\/6+1\/12+1\/20+...+1\/9900]=(1\/2)*[1\/1*2+1\/2*3+1\/3*4+1\/4*5+...+1\/99*100]=(1\/2)*[1-1\/2+1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+...+1\/99-1\/100]=...
如何巧算1\/4+1\/12+1\/24+1\/40+.+1\/19800
1\/4+1\/12+1\/24+1\/40+.+1\/19800 =1\/2(1-1\/2+1\/2-1\/3+1\/3-1\/4+……+1\/99-1\/100)=1\/2(1-1\/100)=99\/200
如何巧算1\/4+1\/12+1\/24+1\/40+...+1\/19800
1\/4+1\/12+1\/24+1\/40+...+1\/19800 =1\/2(1-1\/2+1\/2-1\/3+1\/3-1\/4+……+1\/99-1\/100)=1\/2(1-1\/100)=99\/200 ljt86836祝你学习进步!
1\/4+1\/12+1\/24+1\/40……+1\/19800 算式和结果都要写上,
=99\/100*1\/2 =99\/10000 先从分母中分离出2,再把每个分式分成两个分式的积,然后两数相减,结果一样.如1\/12可先分成1\/6*1\/2 其中1\/6可分成1\/2*3,然后换成1\/2-1\/3以此类推
4分之1+1\/12+1\/24+1\/40…+1\/19800
分母规律为2x2 3x4 4x6 5x8 6x10 …… (n+1)x(2n)19800\/2=9900=99x100,所以n=99 1\/[2nx(n+1)]=(1\/2)[nx(n+1)]=(1\/2)[1\/n - 1\/(n+1)]所以和式为:(1\/2)[1-1\/2 + 1\/2 - 1\/3 + 1\/3 - 1\/4 +……+1\/99 - 1\/100]=(1\/2) x [1-1\/100...
四分之一+十二分之一+二十四分之一+四十分之一...19800分之一
原式=1\/2*3+1\/3*4+1\/4*6+...+1\/19800 =1-1\/2+1\/2-1\/3+1\/3-1\/4+1\/4...+1\/19800 =1-1\/19800 =1\/19899 我也是刚刚学
1\/4十1\/12十1\/24十十十十十1\/19800=?
=1-1/2+1/2-1/3+1/3-1/4+……+1/2005-1/2006 =1-1/2006 =2005/2006 ,本题已解答,如果满意 请点右上角“答案”。
1*1\/3+1\/2*1\/4+1\/3*1\/5+...+1\/98*1\/100这题答案真的是14849\/19800吗...
1\/2-1\/4)\/2+(1\/3-1\/5)\/2+(1\/4-1\/6)\/2+……+(1\/97-1\/99)\/2+(1\/98-1\/100)\/2 =(1-1\/3+1\/2-1\/4+1\/3-1\/5+1\/4-1\/6+...+1\/97-1\/99+1\/98-1\/100)\/2 =(1+1\/2-1\/99-1\/100)\/2 =(3\/2+199\/9900)\/2 =(14651\/9900)\/2 =14651\/19800 ...
好记星的50层魔塔的真魔王打不动啊!
1F:去右中附近,过黄门打蝙蝠[L=85],打初级法师[L=70],打蝙蝠[L=59],进黄门拿钥匙、血瓶和红\/蓝宝石[L=109,A=24,D=28,G=96],然后去4楼。 4F:去左下过黄门,打蝙蝠[L=99]拿2把钥匙,去6楼。 6F:去左下打骷髅[L=71],打绿色史莱姆[不伤],过黄门打蝙蝠[L=61],拿蓝宝石并和老头说话[L=61...
把(1\/1)*2+(1\/2)*3+...+(1\/99
1\/1*2+1\/2*3+1\/3*4···+1\/99*100简便算,!要算式思路 1\/1*2+1\/2*3+1\/3*4···+1\/99*100 =1\/(1×2)+1\/(2×3)+...+1\/(99×100) =(1-1\/2)+(1\/2-1\/3)+...+(1\/99-1\/100) =1-1\/2+1\/2-1\/3+...+1\/99-1\/100 =1-1\/100 =99\/100 ...