若x+y=-1,则x4+5x3y+x2y+8x2y2+xy2+5xy3+y4的值等于______

若x+y=-1,则x4+5x3y+x2y+8x2y2+xy2+5xy3+y4的值等于______.

第1个回答  2014-12-12
∵x+y=-1,
∴x4+5x3y+x2y+8x2y2+xy2+5xy3+y4
=(x4+2x2y2+y4)+5xy(x2+y2)+xy(x+y)+6x2y2
=(x2+y22+5xy[(x+y)2-2xy]+xy(x+y)+6x2y2
=[(x+y)2-2xy]2+5xy(1-2xy)-xy+6x2y2
=(1-2xy)2+5xy-10x2y2-xy+6x2y2
=1-4xy+4x2y2+5xy-10x2y2-xy+6x2y2
=1+(-4xy+5xy-xy)+(4x2y2-10x2y2+6x2y2),
=1.
故答案为:1.
第2个回答  2018-02-13
1

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