若x+y=-1,则x4+5x3y+x2y+8x2y2+xy2+5xy3+y4的值等于______.
.若x+y=-1,则x4+5x3y+x2y+8x2y2+xy2+5xy3+y4的值等于
首先将x4+5x3y+x2y+8x2y2+xy2+5xy3+y4式子拆分项、运用完全平方式逐步整理分解,在整理过程中对于出现的x+y用-1直接代入计算即可.∵x+y=-1,∴x4+5x3y+x2y+8x2y2+xy2+5xy3+y4,=(x4+2x2y2+y4)+5xy(x2+y2)+xy(x+y)+6x2y2,=(x2+y2)2+5xy[(x+y)2-2xy]...
若x+y=-1,则x4+5x3y+x2y+8x2y2+xy2+5xy3+y4的值等于
原式=x4+x3y+4x3y+x2y+4x2y2+4x2y2+xy2+4xy3+xy3+y4,=x3(x+y)+4x2y(x+y)+xy(x+y)+4xy2(x+y)+y3(x+y),=-x3-4x2y-xy-4xy2-y3,=-[(x3+y3)+4xy(x+y)+xy],=-[(x+y)(x2-xy+y2)-4xy+xy],=-[-(x2-xy+y2)-3xy],=(x2-xy+y2...
若x+y=-1,则x^4+5x^3y+x^2y+8x^2y^2+xy^2+5xy^3+y^4的值等
=(x^4+2x^2y^2+y^4)+(5x^3y+5xy^3)+6x^2y^2+xy(x+y)=(x^2+y^2)^2+5xy(x^2+y^2)+6x^2y^2-xy =(x^2+y^2+2xy)(x^2+y^2+3xy)-xy =(x+y)^2·[(x+y)^2+xy]-xy =1·(1+xy)-xy =1 ...
若x+y=-1,则x^4+5x^3y+x^2y+8x^2y^2+xy^2+5xy^3+y^4的值等于( )_百度...
= xy(1-1)+1 =1 二.原式=(x^4+x^3y)+(y^4+xy^3)+(4x^3y+4x^2y^2)+(4xy^3+4x^2y^2)+x^2y+xy^2 =x^3(x+y)+y^3(x+y)+4x^2y(y+x)+4xy^2(y+x)+x^2y+xy^2 =(x+y)(x^3-y^3-4x^2y-4xy^2)+xy^2+x^2y =-x^3-y^3-3x^2y-3xy^2 =-(x^3+...
若x+y=-1,则x的四次方+5x的三次方y+x的平方y+8x的平方y的平方+5xy...
∴x4+5x3y+x2y+8x2y2+xy2+5xy3+y4,=(x4+2x2y2+y4)+5xy(x2+y2)+xy(x+y)+6x2y2,=(x2+y2)2+5xy[(x+y)2-2xy]+xy(x+y)+6x2y2,=[(x+y)2-2xy]2+5xy(1-2xy)-xy+6x2y2,=(1-2xy)2+5xy-10x2y2-xy+6x2y2,=1-4xy+4x2y2+5xy-10x2y2-...
若x+y=-1,则x^4+5x^3y+x^2y+8x^2y^2+xy^2+5xy^3+y^4=(
=(x^4+x^3y)+(y^4+xy^3)+(4x^3y+4x^2y^2)+(4xy^3+4x^2y^2)+x^2y+xy^2 =x^3(x+y)+y^3(x+y)+4x^2y(y+x)+4xy^2(y+x)+x^2y+xy^2 =-x^3-y^3-4x^2y-4xy^2+xy^2+x^2y =-x^3-y^3-3x^2y-3xy^2 =-(x^3+x^2y)-(y^3+xy^2)-2x^2y-2xy^2 =...
若x+y=-1,则x四次方+5x⊃3;y+x⊃2;y+8x⊃2;y⊃2;+xy⊃2...
有题意知道,只要满足X+Y=-1就行,可以用特殊值法,令Y=0,X=-1,则带Y的都为0,所以只有X的4次方=1,答案为1
因式分解的问题,怎么写?
解法:=5x(a+b)+3y(a+b)=(5x+3y)(a+b)说明:系数不一样一样可以做分组分解,和上面一样,把5ax和5bx看成整体,把3ay和3by看成一个整体,利用乘法分配律轻松解出。2. x2-x-y2-y解法:=(x2-y2)-(x+y)=(x+y)(x-y)-(x+y)=(x+y)(x-y-1)利用二二分法,再利用公式法a2-b2=(a+b)(...
...=17,x2y+xy2=66,求:代数式x4+x3y+x2y2+xy3+y4的值
x+y=11时,x、y是方程u2-11u+6=0的两个根∵△2=121-24>0∴此方程有实数根,这时x2+y2=(x+y)2-2xy=109∴x4+x3y+x2y2+xy3+y4=x4+y4+x2y2+xy(x2+y2)=(x2+y2)2-x2y2+xy(x2+y2)=12499.
...y=1,xy=-2.求:(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)的值
若x≠y,且满足等式x^2+2x-5=0和y^2+2y-5=0,那么1\/x+1\/y=? x,y是方程a^2+2a-5=0的两根 所以x+y=-2 xy=-5 1\/x+1\/y=(x+y)\/xy=2\/5 已知x,y满足x^2+y^2-2x-y+5\/4=0,求代数式xy(x+y)的值 解 x²+y²-2x+y+5\/4=0 (x²-2x...