解方程 3\/x-1-(x-2)\/x(x-1)=0
3\/x-1-(x-2)\/x(x-1)=0 3x-(x-2)=0 3x-x+2=0 2x=-2 x=-1 经检验x=-1是原方程的解
解方程:x-3分之2-x+3-x分之1=1(要检验)
3\/(x-1)-(x+2)\/[x(x-1)]=0 [3x-(x+2)]\/[x(x-1)]=0 [2x-2)]\/[x(x-1)]=0 2\/x=0 无解 (2-x)\/(x-3) + 1\/(3-x) = 1 (2-x)\/(x-3) - 1\/(x-3) = 1 (2-x-1)\/(x-3) = 1 (1-x)\/(x-3) = 1 1-x=x-3 2x=4 x=2 经检验不是增根 ∴x...
解方程 3\/x-1=1\/x-2
(1)3\/x-1=1\/x-2 解: 2\/x=-1 x=-2 (2)3\/x-1 - x+2\/x(x-1)=0 解: 3\/x-1-x+(2-2\/x)=0 1\/x-x+1=0 (1-x^2+x)\/x=0 x^2-x-1=0 △=1+4=5 x1=(1+√5)\/2 x2=(1-√5)\/2
解方程3\/x-1 - x+3 \/x²-1=0
3(x+1) -(x+3)=0 3x+3- x -3=0 2x=0 解得:x=0,经检验,满足题意 所以原方程的解为:x=0
解方程:3\/(x-1)(x+2)-x\/x-1+1=0的过程及答案
解:原式=3 \/ (x - 1)(x+2) - x(x+2) \/ (x - 1)(x+2) + (x - 1)(x+2) \/ (x - 1)(x+2)= 3 \/ (x - 1)(x+2) - (x^2+2) \/ (x - 1)(x+2) + (x^2+x - 2) \/ (x - 1)(x+2)= (3 - x^2 - 2+x^2+x - 2) \/ (x - 1)(x+2)=...
解方程3\/x-1 - x+3 \/x²-1=0 过程
方程是不是这样写: 3\/(x-1) - (x+3) \/(x²-1)=0 ,如果是,解答如下:解:由题意可知x²≠1即x≠±1,那么原方程两边同乘以x²-1,可得:3(x+1) -(x+3)=0 3x+3- x -3=0 2x=0 解得:x=0,经检验,满足题意 所以原方程的解为:x=0 ...
解方程:3\/x-1+x+2\/1-x=1
3\/(x-1)-(x+2)\/(x-1)=1 去分母3-(x+2)=x-1 3-x-2=x-1 2x=2 x=1
3x(x-1)=2(x-1)公式法怎么解,求过程
解方程∶1. 移项得∶3x(x-1)-2(x-1)=0 2. 提取公因式得∶(x-1)(3x-2)=0 3. (x-1)=0或(3x-2)=0 当(x-1)=0时,x=1 当(3x-2)=0时,x=2\/3 所以∶x₁=1,ⅹ₂=2\/3
解方程:3(x-1) 2 =x(x-1)
3(x-1)2-x(x-1)=0(x-1)[3(x-1)-x]=0(x-1)(2x-3)=0x-1=0或2x-3=0x1=1,x2=32
解方程3\/2[x-1\/2(x-1)]=2(x-1)
3[x-1\/2(x-1)]=6(x-1)3[x-1\/2x+1\/2]=6x-6 3\/2x+3\/2=6x-6 6x-3\/2x=6+3\/2 9\/2x=15\/2 x=5\/3