关于哲学家就餐中信号量问题

Question

int main()
{
int i;
srand(time(0));

mutex = CreateMutex(NULL, false, NULL);
for (i=0; i<PHILOSOPHER_NUM; i++)
{
semaphore[i] = CreateSemaphore(NULL, 1, 1, NULL);
hPhilosopher[i]=CreateThread(NULL,0,philosopherProc,LPVOID(i), CREATE_SUSPENDED,0);
}
for (i=0; i<PHILOSOPHER_NUM; i++)
ResumeThread(hPhilosopher[i]);
Sleep(2000);
return 0;
}
谁能给解释一下每一行,看了半天还是没理解懂.谢~

Answer 1

int main()
{
int i; 定义变量
srand(time(0)); 随机生成时间并转化为整形

mutex = CreateMutex(NULL, false, NULL); 初始化信号量为false
for (i=0; i<PHILOSOPHER_NUM; i++)
{
semaphore[i] = CreateSemaphore(NULL, 1, 1, NULL); 将哲学家对应的信号量初始化为1

hPhilosopher[i]=CreateThread(NULL,0,philosopherProc,LPVOID(i), CREATE_SUSPENDED,0); 创建各个哲学家的执行的进程
}
for (i=0; i<PHILOSOPHER_NUM; i++)
ResumeThread(hPhilosopher[i]);
Sleep(2000); 睡眠2000ms
return 0;
}