已知1\/x-1\/y=5,2x-3xy-2y\/x+2xy-y的值
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已知1\/x-1\/y=5,求分式2x+3xy-2y\/x-2xy-y的值
已知1\/x-1\/y=3,求分式2x+3xy-2y\/x-2xy-y的值 根据条件可得y-x=3xy(方程1\/x-1\/y=3两边同乘xy)所以分式的分子可以化简为2x+3xy-2y =2(x-y)+3xy =-6xy+3xy =-3xy 分式的分母x-2xy-y =-3xy-2xy=-5xy 所以答案为3\/5(五分之三)...
已知1\/x-1\/y=5,则2x+3xy-2y\/y+2xy-x的值
1\/x-1\/y=5 (y-x)\/xy=5 y-x=5xy x-y=-5xy (2x+3xy-2y)\/(y+2xy-x)=[2(x-y)+3xy]\/[-(x-y)+2xy]=[-10xy+3xy]\/[5xy-3xy]=-7\/2
已知1\/x-1\/y=5,求分式2x+3xy-2y\/x-2xy-y的值
1\/x+1\/y=5 y+x=5xy x+y=5xy 所以 2x-3xy+2y\/x+2xy+y =[2(x+y)-3xy]\/[(x+y)+2xy]=(2*5xy-3xy)\/(5xy+2xy)=7xy\/7xy =1
已知:x分之一减y分之一等于5,求x-2xy-2y分之2x+3xy-2y的值
解:1\/x - 1\/y = 5.通分整理得,(y - x )\/xy =5 即y - x = 5xy 然后把后边的分式分子分母中整理,比如 分子2x +3xy - 2y就整理成2(x - y)+3xy 代换成 2.(-5xy)+3xy =-7xy ,分母也这样整理。 最后分子分母约分可得结果。我只告诉你算理。不过看样子你这题应该是题目...
已知1\/x-1\/y=5,求(2x+4xy-2y)\/x-3xy-y)的ŀ
(2x+4xy-2y)\/x-3xy-y)分子分母都除以xy得 =(2\/y+4-2\/x)\/(1\/y-3-1\/x)=(4-10)\/(-3-5)=-6\/-8 =3\/4
已知1\/x+1\/y=5,求(2x-3xy+2y)\/(x+2xy+y)的值
1\/x+1\/y=5 两边都乘以xy y+x=5xy 所以:(2x-3xy+2y)\/(x+2xy+y)=[2(x+y)-3xy]\/[(x+y)+2xy]=(10xy-3xy)\/(5xy+2xy)=7xy\/7xy =1
若1\/x-1\/y=3,则分式2x+3xy-2y\/x-2xy-y 的值为多少
1\/x-1\/y=3 1\/y-1\/x=-3 2x+3xy-2y\/x-2xy-y 分子分母同除以xy得:原式=[2(1\/y-1\/x)+3]\/[(1\/y-1\/x)-2]=(-6+3)\/(-3-2)=3\/5
已知1\/x-1\/y=5求3x+5xy-3y\/x+2xy-y
首先化简通分1\/x+1\/y=5得: (x+y)\/xy=5 即有x+y=5xy 将要求的分式化简: 3x+xy+3y\/x-2xy+y =3x+3y+xy\/x+y-2xy (根据加法交换律) =3(x+y)+xy\/(x+y)-2xy =15xy+xy\/5xy-2xy(将x+y=5xy代入) =16xy\/3xy =16\/3 ...
已知1\/x+1\/y=5,求分式2x-3xy+2y\/x+2xy+y的值
∵1\/x+1\/y=5 ∴(2x-3xy+2y)\/(x+2xy+y)=(2\/y-3+2\/x)\/(1\/y+2+1\/x) ...【分子分母同除以xy】={2(1\/x+1\/y)-3}\/{(1\/x+1\/y)+2} =(2*5-3)\/(5+2)=7\/7 =1