1/1X2+1/2X3+1/3X4+...+1/99X100
=ï¼1-1/2ï¼+(1/2-1/3)+(1/3-1/4)+...+(1/99-1/100)
=1-1/2+1/2-1/3+1/3-1/4+...+1/99-1/100 ï¼ä¸é´ä¸¤é¡¹ä¸¤é¡¹æ£è´æµæ¶ï¼
=1-1/100
=99/100
1\/1x2+1\/2x3+1\/3x4+...1\/99x100
解：1\/1X2+1\/2X3+1\/3X4+...+1\/99X100 =（1-1\/2）+(1\/2-1\/3)+(1\/3-1\/4)+...+(1\/99-1\/100)=1-1\/2+1\/2-1\/3+1\/3-1\/4+...+1\/99-1\/100 （中间两项两项正负抵消）=1-1\/100 =99\/100
1\/1X2+1\/2X3+1\/3X4+…… +1\/99X100=?
1\/1X2+1\/2X3+1\/3X4+...+1\/99X100 =（1-1\/2）+(1\/2-1\/3)+(1\/3-1\/4)+...+(1\/99-1\/100)=1-1\/100 =99\/100 乘法分配律 简便计算中最常用的方法是乘法分配律。乘法分配律指的是ax(b+c)=axb+axc其中a,b,c是任意实数。相反的，axb+axc=ax(b+c)叫做乘法分配律的逆运用...
1\/1X2+1\/2X3+1\/3X4...1\/99X100
1\/1X2+1\/2X3+1\/3X4+...+1\/99X100 = 1\/1-1\/2+1\/2-1\/3+1\/3-...+1\/99-1\/00 = 1-1\/100 = 99\/100
1\/1X2+1\/2x3+1\/3x4+1\/4x5+...+1\/98x99+1\/99x100求结果!!!
1\/1乘2等于1\/1减1\/2 同理2乘3分之一等于2分之一减去3分之一 上式等于1\/1-1\/2+1\/2--1\/3+1\/3...-1\/99+1\/99-1\/100等于99\/100
巧算分数 1\/1X2 + 1\/2x3 + 1\/3X4 + .+ 1\/99X100 (一组分数在一起.已...
1\/1X2 + 1\/2x3 + 1\/3X4 + . + 1\/99X100 =1-1\/2+1\/2-1\/3+1\/3-1\/4+……+1\/99-1\/100 =1-1\/100 =99\/10
1\/1X2+1\/2X3+1\/3X4+...+1\/99+100=
题目给错了吧？ 最后一项应该是1\/99X100吧？1\/1X2+1\/2X3+1\/3X4+...+1\/99X100 =（1-1\/2）+(1\/2-1\/3)+(1\/3-1\/4)+...+(1\/99-1\/100)=1-1\/100 =99\/100
数学计算题:1\/1X2+1\/2X3+1\/3X4+...+1\/99x100=? 请写出计算过程~_百度...
1\/1*2=1\/1-1\/2 1\/2*3=1\/2-1\/3……所以原式=1-1\/2+1\/2-1\/3+1\/3-1\/4+……-1\/99+1\/99-1\/100=99\/100
求解答:1\/1x2+1\/2x3+1\/3x4...1\/99x100. 奥数不会
这个是有裂项公式的，1\/n(n+1)=1\/n-1\/(n+1)根据公式，原式=1-1\/2+1\/2-1\/3+……-1\/99+1\/99-1\/100 中间的式子都可以抵消，则得到原式=1-1\/100=99\/100
一道数学题急 1\/1x2+1\/2x3+1\/3x4+...+1\/99x100=?
1\/1x2+1\/2x3+1\/3x4+...+1\/99x100 =1-1\/2+1\/2-1\/3+.+1\/98-1\/99+1\/99-1\/100 =1-1\/100 =99\/100
乘法的分配律怎么算?
乘法分配律指的是两个数的和与一个数相乘的积，可以先把它们分别与这个数相乘再相加，结果不变乘法分配律是简便计算中最常用的方法。举例
