=1-2(sin(x/2))^2 +1
=2- 2(sin(x/2))^2
f(x)=2-2x^2
f(cos(x/2)^2=2-2(cos(x/2))^2
=2-(1+cosx)
=1-cosx本回答被提问者采纳
已知f(sin x\/2)=cosx+1,则f(cos x\/2)=?
f(sinx\/2)=cosx+1 =1-2(sin(x\/2))^2 +1 =2- 2(sin(x\/2))^2 f(x)=2-2x^2 f(cos(x\/2)^2=2-2(cos(x\/2))^2 =2-(1+cosx)=1-cosx
...数学关于复合函数的题;f (sin x\/2)=1+cosx ,则f (cos x\/2)=...
f (sin x\/2)=1+cosx =1+(1-2sin x\/2)=-2sin x\/2+2 所以 f (cos x\/2)=－2cos x\/2＋2,2,f(sin x\/2)=1+cosx =(cos x\/2)^2+(sin x\/2)^2+(cos x\/2)^2-(sin x\/2)^2 =2*(cos x\/2)^2 =2*(1-(sin x\/2)^2)换元,令 t=sin x\/2 则f(t)=2*(1-t...
f(sinx\/2)=cosx+1,则f(cosx\/2)=___?要有过程
利用2倍角公式f(sinx\/2)=cosx+1=1-2(sinx\/2)^2+1 =2-2(sinx\/2)^2令sinx\/2=t f(t)=2-2t^2 t换回x f(x)=2-2x^2 f(cosx\/2)=2-2(cosx\/2)^2=2-2(cosx+1)\/2=1-cosx 1 1 已赞过 已踩过< 你对这个回答的评价是? 评论 分享 微信扫一扫 网络繁忙请稍后重试 新浪微博 QQ空间 ...
已知f(sinx\/2)=cosx+1,则f(cosx\/2)等于多少
f(sinx\/2)=cosx+1=2-2sin²x\/2 所以 f(x)=2-2x²f(cosx\/2)=2(1-cos²x\/2)=2sin²x\/2
已知f(sin2分之x)=cosx+1,则f(cos2分之x)等于什么
f(sin(x\/2))=cosx+1 =1-2(sin(x\/2))^2+1 =2-2(sin(x\/2))^2 令y=sin(x\/2)则f(y)=2-2y^2 令y=cos(x\/2)f(cos(x\/2))=2-2(cos(x\/2))^2 =2(sin(x\/2))^2
已知f(sin(x\/2))=cosx+1,求f(cos(x\/2))
2就是把b化成a的一个函数.再直接把a换成x就可以了.说得很模糊吧.举个简单的例子吧.f(x+1)=x+2,求f(x).1:此中a=x+1,那么x=a-1,即f(x)=(x-1)+2=x+1.2:f(x+1)=(x+1)+1,直接得f(x)=x+1.这个是最简单的,更多的还是要自己去体会.
已知f(sinx\/2)=cosx+1,求f(x)及f(cosx\/2).要全解题过程。谢谢!_百度...
f(sinx\/2)=cosx+1=1-2(sinx\/2)^2+1=2-2(sinx\/2)^2 令sinx\/2=t 即得f(t)=2-2t^2 即f(x)=2-2x^2 f(cosx\/2)=2-2(cosx\/2)^2=2-2[(cosx+1)\/2]^2=2-2*(cosx+1)\/2 =2-(cosx+1)=1-cosx
已知f(sin x\/2)=1+cos x,则f(cos x\/2)= 多少?
设x\/2=α，根据三角函数倍角公式 cos2α=(cosα)^2-(sinα)^2=2(cosα)^2-1=1-2(sinα)^2,则有f(sinα)=1+cos2α=1+[1-2(sinα)^2]=2-2(sinα)^2，所以 f（cosx\/2)=2-2(cosx\/2）^2=1-[2(cosx\/2）^2-1]=1-cosx 。故 f(cosx\/2)=1-cosx 。
设f(sinx\/2)=1+cosx,则f(cosx\/2)等于多少
令sinx\/2=t f(t)=1+1-2t^2=2-2t^2 f(cosx\/2)=2-2(cosx\/2)^2 =2-2(1+cosx)\/2 =1-cosx
f(sin X\/2 )=cosx+1 求f(x)
f(sin X\/2 )=cosx+1 =1-2(sinx\/2)^2+1 =2-2(sinx\/2)^2 取sinx\/2为x,则 f(x)=2-2x^2.
