设函数z=ln y\/x,则dz=?
因为这里书写不便,故将我的答案做成图像贴于下方,谨供楼主参考(若图像显示过小,点击图片可放大)
求z=ln(y\/x) 的全微分dz= __
= x\/y dy + x\/y * (-y\/x²)dx = xdy\/y - dx\/x
设x\/z=ln(y\/x)求dz,应该用什么公式去求?能否把过程告诉
z=x\/(ln(y\/x))pz\/px=( ln(y\/x) - x *y\/x * -y\/x^2)\/(ln(y\/x)^2)=(ln(y\/x) -(y\/x)^2 )\/(ln(y\/x)^2)pz\/py=(x*y\/x*1\/x )\/(ln(y\/x)^2)=(y\/x)\/(ln(y\/x)^2)dz=pz\/px*dx+pz\/py*dy pz\/px代表偏导数 ...
Z=ln(y\/x)怎么求偏导数 求z=x^(xy)的偏导数
z'y=(1\/x)\/(y\/x)=1\/y dz=z'xdx +z'ydy u=ln(x^2+y^2+z^2)u'x=2x\/(x^2+y^2+z^2)u'y=2y\/(x^2+y^2+z^2)u'z=2z\/(x^2+y^2+z^2)du=2x\/(x^2+y^2+z^2) dx + 2y\/(x^2+y^2+z^2) dy + 2z\/(x^2+y^2+z^2) dz ...
x\/z=ln(z\/y)求dz
简单计算一下,答案如图所示
若z=ylnx,则dz等于( )A.ylnxlnyx+ylnxlnyyB.ylnxlnyxC.ylnxlnydx+y...
由z=ylnx,得zx=ylnx?1x=ylnxx,zy=lnx?ylnx?1=ylnxlnxy∴dz=ylnxxdx+ylnxlnxydy故选:D
设方程x=ln(y\/x)确定函数z=z(x,y),求全微分dz.
x=ln(y\/x)e^x=y\/x y=xe^x dy=(xe^x+e^x)dx dz=Zxdx+Zydy=[Zx+Zy(xe^x+e^x)]dx
z=lnx\/y 则dz|(1,1)=?
答:你要表示的是ln(x\/y)么?这里按ln(x\/y)做.dz=(1\/y)\/(x\/y)dx+(-x\/y^2)\/(x\/y)dy =1\/xdx-1\/ydy 代入x=1,y=1 dz|x=1,y=1 =dx-dy
x=zlnz\/y,则dz=?
简单计算一下,答案如图所示
z=lnx\/y 则dz|(1,1)=?
答:你要表示的是ln(x\/y)么?这里按ln(x\/y)做.dz=(1\/y)\/(x\/y)dx+(-x\/y^2)\/(x\/y)dy =1\/xdx-1\/ydy 代入x=1,y=1 dz|x=1,y=1 =dx-dy