3x^3-5x^2+5x-2 因式分解

如题所述

第1个回答  2022-08-15
3x^3-5x^2+5x-2
=3x^3-3x^2+3x-2x^2+2x-2
=3x(x^2-x+1)-2(x^2-x+1)
=(x^2-x+1)(3x-2)

3x^3-5x^2+5x-2 因式分解
3x^3-5x^2+5x-2 =3x^3-3x^2+3x-2x^2+2x-2 =3x(x^2-x+1)-2(x^2-x+1)=(x^2-x+1)(3x-2)

3x3次方加5x平方减2因式分解
3x^3+5x^2-2 =(3x^3+3x^2)+(2x^2-2)=(3x^2)(x+1)+2(x+1)(x-1)=(x+1)(3x^2+2x-2)

3x^2+5x-2因式分解
3x^2+5x-2 =(3x-1)(x+2)

因式分解:X^3-5X^2+6X-2
(x-1)(x^2+4x+2)

3x^3-5x^2+8X-24因式分解
3x^3-5x^2+8x-24 =3x^3-3*2.1534589x^2+1.4603767x^2-1.4603767*2.1534589x+11.14486120196763x-24 =3x^2(x-2.1534589)+1.4603736x(x-2.1534589)+11.14486095(x-2.1534589)=(x-2.1534589)(3x^2+1.4603736x+11.14486095)=3(x-2.1534589)(x^2+0.4867912x+3.71495365)此为...

x^3-4x^2+5x-2因式分解
(X^3-4X^2+4X)+(X-2)=X(X-2)^2+(X-2)=(X-2)[X(X-2)+1]=(X-2)(X-1)^2。

y=3x^3-5x^2-11x-3的因式分解
可设分解结果为:(3x+a)(x²+bx+c)展开为:3x³+(a+3b)x²+(ab+3c)x+ac 对照分解前各项系数,可得如下方程:a+3b=-5 ab+3c=-11 ac=-3 解出这个方程,可得:a=1, b=-2, c=-3 所以 y=3x³-5x²-11x-3=(3x+1)(x²-2x-3) =(3x+1)(...

x^3-4x^2+5x-2=0因式分解,怎么分啊
x^3 - 4x^2 + 5x - 2 = 0 ( x^3 - 4x^2 + 4x ) + ( x - 2 ) = 0 x( x^2 - 4x + 4 ) + ( x - 2 ) = 0 x( x - 2 )^2 + ( x - 2 ) = 0 ( x - 2 )( x^2 - 2x + 1) = 0 ( x - 2 )( x - 1 )^2 = 0 所以,x = 1或x = 2....

因式分解 3X^2﹢5X‐2
3x^2+5x-2 =(3x-1)(x+2)

3x^2-5x-2因式分解
3x^2-5x-2=(3x+1)(x-2)

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