=（1-（x+1）²）/(x+1)×(x+1)(x-1)
=(-x²-2x)(x-1)
=-x(x-1)(x+2)
=-1/2×(1/2-1)×(1/2+2)
=-1/2×(-1/2)×(5/2)
=5/8;本回答被提问者采纳
先化简再求值x+2分之x的平方+2x+1除以x-1分之x的平方
x+1分之1-1-x)除以x 的平方-1分之1 =（1-（x+1）²）\/(x+1)×(x+1)(x-1)=(-x²-2x)(x-1)=-x(x-1)(x+2)=-1\/2×(1\/2-1)×(1\/2+2)=-1\/2×(-1\/2)×(5\/2)=5\/8;
...x+2分之1-x+2分之x的平方+2x+1除以x-1分之x的平方-1其中x=根号2-2...
原式=[1\/(x+2)]-[(x+2x+1)\/(x+2)]÷[(x-1)\/(x-1)] =[1\/(x+2)]-[(x+1)\/(x+2)]÷[(x+1)(x-1)\/(x-1)] =[1\/(x+2)]-[(x+1)\/(x+2)]÷(x+1) =[1\/(x+2)]-[(x+1)\/(x+2)]×[1\/(x+1)] =[1\/(x+2)...
...x+2分之1-x+2分之x的平方+2x+1除以x-1分之x的平方-1其中x=根号2-2...
原式=[1\/(x+2)]-[(x+2x+1)\/(x+2)]÷[(x-1)\/(x-1)] =[1\/(x+2)]-[(x+1)\/(x+2)]÷[(x+1)(x-1)\/(x-1)] =[1\/(x+2)]-[(x+1)\/(x+2)]÷(x+1) =[1\/(x+2)]-[(x+1)\/(x+2)]×[1\/(x+1)] =[1\/(x+2)...
...再求值。x+2分之x-x+2分之x平方+2x+1除以x-1分之x平方-1 其中x=根 ...
x+2分之x-x+2分之x平方+2x+1除以x-1分之x平方-1 =[x\/(x+2)-(x²+2x+1)\/(x+2)]÷(x²-1)\/(x-1)=[(x-x²-2x-1)\/(x+2)]÷(x+1)=(-x²-x-1)\/(x+2)(x+1)=(-x²-x-1)\/(x²+3x+2) 其中x=根号3 =[-(√3)²...
先化简再求值:x+2分之1-x^2-x分之x^2-4x+4÷(x+1-x-1分之3),其中x是...
]=1\/(x+2)-[(x-2)^2\/(x-1)x]\/[(x^2-1-3)\/(x-1)]=1\/(x+2)-[(x-2)^2\/(x^3-4x)]=[(x^3-4x)-(x+2)(x-2)^2]\/[(x+2)(x^3-4x)]=(x^2-4)(x-x+2)\/(x^2-4)(x^2+2x)=2\/(x^2+2x)x=3 时，原式=2\/(3^2+2*3)=2\/(9+6=2\/15 ...
先化简,再求值:x+2分之1 - x+2分之二次方+2x+1 ÷ x-1分之x二次方-1...
先化简，再求值：x+2分之1 - x+2分之二次方+2x+1 ÷ x-1分之x二次方-1 ，其中x=根号2-2 =(1\/x+2)-(x+1)²\/(x+2)÷(x²-1)\/(x-1)=1\/(x+2)-(x+1)\/(x+2)=-x\/(x+2);x=√2-2;x+2=√2;所以原式=-(√2-2)\/√2=-1+√2;如果本题有什么不...
先化简再求值:(x+2\/x的平方
先 化简 ,再 求值 :x+2分之x的平方+4x+4除以(x的平方+2x),其中x= 根号 下2 原式=(x+2)²\/(x+2)÷x(x+2)=(x+2)*1\/x(x+2)=1\/x =√2\/2
先化简再求值x^2+x\/x^2-2x+1
应该加括号的 x（x+1）\/（x-1）^2 采纳吧
...之2x的平方-4x乘以x的平方-4x+ 4分之x的平方+2x+ 2-x分之4x(其中x...
∵x=-1\/2 ∴2x=2×(-1\/2)=-1
是先化简,再求值,(X+2分之X
x+2分之x的平方+4x+4除以(x的平方+2x),其中x=根号下2 （x^2+4x+4）\/(x+2)÷（x^2+2x）=（x+2)^2\/(x+2)÷[x（x+2）]=1\/x =1\/√2 =√2\/2
