=[x/(x+2)-(x²+2x+1)/(x+2)]÷(x²-1)/(x-1)
=[(x-x²-2x-1)/(x+2)]÷(x+1)
=(-x²-x-1)/(x+2)(x+1)
=(-x²-x-1)/(x²+3x+2) 其中x=根号3
=[-(√3)²-√3-1)]/[(√3)²+3*√3+2]
=(-4-√3)/(5+3√3)
=(-4-√3)(5-3√3)/(5+3√3)(5-3√3)
=(-20-5√3+12√3+9)/(25-27)
=(-11+7√3)/(-2)
=(11-7√3)/2
...x+2分之x-x+2分之x平方+2x+1除以x-1分之x平方-1 其中x=根号3_百度...
x+2分之x-x+2分之x平方+2x+1除以x-1分之x平方-1 =[x\/(x+2)-(x²+2x+1)\/(x+2)]÷(x²-1)\/(x-1)=[(x-x²-2x-1)\/(x+2)]÷(x+1)=(-x²-x-1)\/(x+2)(x+1)=(-x²-x-1)\/(x²+3x+2) 其中x=根号3 =[-(√3)²...
...再求值x+2分之1-x+2分之x的平方+2x+1除以x-1分之x的平方-1其中x=根...
原式=[1\/(x+2)]-[(x+2x+1)\/(x+2)]÷[(x-1)\/(x-1)] =[1\/(x+2)]-[(x+1)\/(x+2)]÷[(x+1)(x-1)\/(x-1)] =[1\/(x+2)]-[(x+1)\/(x+2)]÷(x+1) =[1\/(x+2)]-[(x+1)\/(x+2)]×[1\/(x+1)] =[1\/(x+2)...
...再求值x+2分之1-x+2分之x的平方+2x+1除以x-1分之x的平方-1其中x=根...
原式=[1\/(x+2)]-[(x+2x+1)\/(x+2)]÷[(x-1)\/(x-1)] =[1\/(x+2)]-[(x+1)\/(x+2)]÷[(x+1)(x-1)\/(x-1)] =[1\/(x+2)]-[(x+1)\/(x+2)]÷(x+1) =[1\/(x+2)]-[(x+1)\/(x+2)]×[1\/(x+1)] =[1\/(x+2)...
先化简再求值:x+2分之1-x^2-x分之x^2-4x+4÷(x+1-x-1分之3),其中x是...
=(x^2-4)(x-x+2)\/(x^2-4)(x^2+2x)=2\/(x^2+2x)x=3 时，原式=2\/(3^2+2*3)=2\/(9+6=2\/15
先化简,再求值:x+2分之1 - x+2分之二次方+2x+1 ÷ x-1分之x二次方-1...
先化简，再求值：x+2分之1 - x+2分之二次方+2x+1 ÷ x-1分之x二次方-1 ，其中x=根号2-2 =(1\/x+2)-(x+1)²\/(x+2)÷(x²-1)\/(x-1)=1\/(x+2)-(x+1)\/(x+2)=-x\/(x+2);x=√2-2;x+2=√2;所以原式=-(√2-2)\/√2=-1+√2;如果本题有什么不...
先化简,再求值:(1-x+2分之1)除以x的平方-4分之x的平方+2x+1,其中x...
1\/(1-x+2)\/(x^2+2x+1)\/(x^2-4),其中x=-3 =1\/(3-x)*(x+2)(x-2)\/(x+1)^2 =(x+2)(x-2)\/(x+1)^2(3-x)=5\/24
x+2分之x平方+2x+1÷x-1分之x平方-1减x+2分之1
原式=[(x+1)^2\/(x+2)] ÷[(x-1)(x+1)\/(x-1)]-1\/(x+2)=(x+1)\/(x+2)-1\/(x+2)=x\/(x+2)。
先化简后计算x^2+x分之x^2-1÷(x-x分之2x-1),其中x是一元二次方程x^2...
原式=[(x^2-1)\/(x^2+x)]\/[x-(2x-1)\/x]=[(x-1)(x+1)\/x(x+1)]\/[(x-1)^2\/x]=1\/(x-1)，x^2-2x-2=0——》x1=v3+1>0，x2=-v3+1<0，所以x=v3+1，将其代入上式，得：原式=v3\/3。
...先化简,再求值:(X-1)分之X-(X+1)分之X除以(1-X)分之2X,其中X等于根 ...
X\/(X-1)-X\/(X+1)÷2X\/(1-X)=X\/(X-1)+(2X^2)\/[(X+1)(X-1)]=[X(X+1)]\/[(X+1)(X-1)]+(2X^2)\/[(X+1)(X-1)]=(3X^2+X)\/[(X+1)(X-1)]=(3X^2+X)\/(X^2-1)当X=根3时 原式=（9+√3）\/(3-1)=9\/2+√3\/2....
先化简再求值 (x+1分之3x-x-1分之x)÷x^2 -1分之x-2其中x=2分之根号3...
用平方差公式 (3x*(x-1)\/(x^2-1)) - (x*(x+1)\/(x^2-1)) + (x-2)\/(x^2-1)=(2x^2-3x-2)\/(x^2-1)=2+6√3 同学你好，如果问题已解决，记得右上角采纳哦~~~您的采纳是对我的肯定~谢谢哦
