=99-(2/1+6/1+12/1+20/1+30/1+â¦â¦+9702/1+9900/1ï¼
=99-ï¼1-2/1+2/1-3/1+3/1-4/1+4/1-5/1+5/1-6/1+â¦â¦+98/1-99/1+99/1-100/1ï¼
=99-ï¼1-100/1ï¼
=98å100/1
=98.01追é®
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追ç2/1+6/5+12/11+20/19+30/29····9702/9701+9900/9899
=99-(2/1+6/1+12/1+20/1+30/1+â¦â¦+9702/1+9900/1ï¼
=99-ï¼1-2/1+2/1-3/1+3/1-4/1+4/1-5/1+5/1-6/1+â¦â¦+98/1-99/1+99/1-100/1ï¼
=99-ï¼1-100/1ï¼
=98å100/1
=98.01
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2\/1+6\/5+12\/11+20\/19+30\/29···9702\/9701+9900\/9899进行简算
2\/1+6\/5+12\/11+20\/19+30\/29···9702\/9701+9900\/9899 =99-(2\/1+6\/1+12\/1+20\/1+30\/1+……+9702\/1+9900\/1）=99-（1-2\/1+2\/1-3\/1+3\/1-4\/1+4\/1-5\/1+5\/1-6\/1+……+98\/1-99\/1+99\/1-100\/1）=99-（1-100\/1）=98又100\/1 =98.01 ...
...19+30分之29+..+9702分之9701+9900分之9899 简算
=100-1+1\/100=99+1\/100=9901\/100
简算1\/2+5\/6+11\/12+29\/30+...+9701\/9702+9899\/9900
=99-1+1\/100 =98.01
问一道简算题
1\/2+5\/6+11\/12+19\/20+29\/30+．．．+9701\/9702+9899\/9900 =1\/2+（1-1\/6）+（1-1\/12）+（1-1\/20）+（1-1\/30）+……+（1-1\/9702）+（1-1\/9900）=1\/2+[1-（1\/2-1\/3）]+[1-（1\/3-1\/4）]+[1-（1\/4-1\/5）]+[1-（1\/5-1\/6）]+……+[1-（1\/98-1\/99...
1\/2+1\/6+1\/12+1\/20+1\/30...+1\/9900(简算)
分母的规律是：N*(N+1),然后可以分化成1-1\/2+1\/2-1\/3+1\/N-1\/(N+1)= 1-1\/(N+1);所以答案应该是9899\/9900. 好久不碰数学了，不知道对不对～～呵呵
99乘99又98\/99简算,快点,今天给答案,我给高分!!!
如果没有理解错，应该是这样
...一加三乘四分之一省略号加九十九乘一百分之一简算
1\/2+2\/3+3\/4+4\/5……+99\/100 =1-1\/2+1-1\/3+1-1\/4+1-1\/5……+1-1\/100 =99-(1\/2+1\/3+1\/4+1\/5+……+1\/100)=99-(99*100-1)\/（99*100）=98又9899\/9900
简算2-6\/13÷9\/26-2\/3 (28+2\/7×7\/8)×25% 99又 98\/99×99
2-6\/13÷9\/26-2\/3 =2-6\/13×26\/9-2\/3 =2-4\/3-2\/3 =0 （28+2\/7×7\/8）×25 =(28+1\/4)×1\/4 =28×1\/4+1\/4×1\/4 =7+1\/16 =7又1\/16 99又 98\/99×99 =(100-1\/99)×99 =100×99-1\/99×99 =9900-1 =9899 ...
2\/1+6\/5+12\/11+20\/19+30\/29···9702\/9701+9900\/9899进行简算
2\/1+6\/5+12\/11+20\/19+30\/29···9702\/9701+9900\/9899=99-(2\/1+6\/1+12\/1+20\/1+30\/1+……+9702\/1+9900\/1）=99-（1-2\/1+2\/1-3\/1+3\/1-4\/1+4\/1-5\/1+5\/1-6\/1+……+98\/1-99\/1+99\/1-100\/1）=99-（1-100\/1）=98又100\/1=98......
2分之1 + 6分之5 + 12分之11 +20分之19 +...+ 99×100 分之9899 求...
=(1-1\/2)+(1-5\/6)+(1-11\/12)+(1-19\/20)+...+(1-9899\/9900)=99-(1\/2+1\/6+1\/12+1\/20+...+1\/9900)=99-[(1-1\/2)+(1\/2-1\/3)+(1\/3-1\/4)+(1\/4-1\/5)+...+(1\/99-1\/100)]=99-(1-1\/100)=99-99\/100 =9801\/100 打字不易，请采纳！不明白追问哦！
