如题所述
第二张,我圈出来的,,不懂,能给我解释解释吗
dx^2 = 2x dxxdx =(1/2) dx^2dlnx = (1/x) dx∫ xlnx dx=(1/2)∫ lnx dx^2=(1/2)x^2.lnx - (1/2)∫ x^2 dlnx=(1/2)x^2.lnx - (1/2)∫ x dx=(1/2)x^2.lnx - (1/4)x^2 + C