汇编语言实现从键盘上接收两个一位十六进制数据,求其和,并以十进制形式显示出来

Answer 1

DATA SEGMENT
STRING1 DB 0dh,0ah,'Please input the first numbers:',0AH,0DH,'$'
STRING2 DB 0dh,0ah,'Please input the second numbers:',0AH,0DH,'$'
STRING3 DB 0dh,0ah,'The total is:',0AH,0DH,'$'
STRING4 DB 0dh,0ah,'OVERFLOW!',0AH,0DH,'$'
NUM1 DB 4 DUP(0)

numm1 dw 0
numm2 dw 0
NUM2 DB 4 DUP(0)

DATA1 DW 2 DUP(?)
CR DB 0DH,0AH,'$'
DATA ENDS

CODE SEGMENT
ASSUME DS:DATA,CS:CODE
START:MOV AX,DATA
MOV DS,AX

LEA DX,STRING1 ;9号功能,显示字符串1输入第一个数
MOV AH,09H
INT 21H
LEA SI,NUM1
Mov cx,4
INPUT1:
MOV AH,01H
INT 21H

sub al,30h
MOV [SI],AL
INC SI
loop INPUT1

LEA DX,STRING2 ;9号功能,显示字符串2输入第二个数
MOV AH,09H
INT 21H
LEA SI,NUM2
mov cx,4
INPUT2:
MOV AH,01H
INT 21H

sub al,30h
MOV [SI],AL
INC SI
loop INPUT2

LEA SI,NUM1
MOV BH,0
MOV BL,[SI]
MOV AX,4096
MOV DX,0
MUL BX
ADD NUMM1,AX
INC SI
MOV BH,0
MOV BL,[SI]
MOV AX,256
MOV DX,0
MUL BX
ADD NUMM1,AX
INC SI
MOV BH,0
MOV BL,[SI]
MOV AX,16
MOV DX,0
MUL BX
ADD NUMM1,AX
INC SI
MOV AL,[SI]
MOV AH,0
ADD NUMM1,AX

LEA SI,NUM2
MOV BH,0
MOV BL,[SI]
MOV AX,4096
MOV DX,0
MUL BX
ADD NUMM2,AX
INC SI
MOV BH,0
MOV BL,[SI]
MOV AX,256
MOV DX,0
MUL BX
ADD NUMM2,AX
INC SI
MOV BH,0
MOV BL,[SI]
MOV AX,16
MOV DX,0
MUL BX
ADD NUMM2,AX
INC SI
MOV AL,[SI]
MOV AH,0
ADD NUMM2,AX

MOV AX,NUMM1
ADD AX,NUMM2
JC L1

PUSH AX
LEA DX,STRING3 ;9号功能,显示和
MOV AH,09H
INT 21H

POP AX ;判溢出,CF=1有溢出,跳到L1处
MOV DX,0 ;无符号按字除 (DX,AX)/源操作数
MOV CX,10000 ;AX:商 ,DX:余数
DIV CX
PUSH DX ;余数DX入栈
MOV AH,0
MOV DL,AL
ADD DL,30H ;0--65535,除10000后AX高八位为0,将商放在DL里
MOV AH,02H ;2号功能输出商即十进制最高位
INT 21H

POP DX
mov ax,dx
mov dx,0
MOV CX,1000 ;余数DX出栈作为除数
DIV CX
PUSH DX
MOV AH,0
MOV DL,AL
ADD DL,30H
MOV AH,02H
INT 21H

POP DX
mov ax,dx
mov dx,0
MOV CX,100
DIV CX
PUSH DX
MOV AH,0
MOV DL,AL
ADD DL,30H
MOV AH,02H
INT 21H

POP DX
mov ax,dx
mov dx,0
MOV CX,10
DIV CX
PUSH DX
MOV AH,0
MOV DL,AL
ADD DL,30H
MOV AH,02H
INT 21H

POP DX
add dl,30h
MOV AH,02H
INT 21H
jmp exit
L1: LEA DX,STRING4
MOV AH,09H
INT 21H
EXIT: MOV AH,4CH ;返回DOS
INT 21H

CODE ENDS
END START