解ï¼F(xï¼y)=y-cos(x+y)â¡0ï¼æ dy/dx=-(∂F/∂x)/(∂F/∂y)=-sin(x+y)/[1+sin(x+y)]
dy/dx = dcos(x + y)/d(x + y) · d(x + y)/dx，链式法则
dy/dx = - sin(x + y) · (1 + dy/dx)
dy/dx = - sin(x + y) - sin(x + y) · dy/dx
dy/dx · [1 + sin(x + y)] = - sin(x + y)
dy/dx = - sin(x + y)/[1 + sin(x + y)
dy/dx = - 1/[1 + csc(x + y)]本回答被提问者和网友采纳
求:由方程所确定的隐函数的导数dy\/dx? y=cos(x+y)
求:由方程y=cos(x+y)所确定的隐函数的导数dy\/dx?解：F(x，y)=y-cos(x+y)≡0；故dy\/dx=-(∂F\/∂x)\/(∂F\/∂y)=-sin(x+y)\/[1+sin(x+y)]
求由方程所确定的隐函数的导数dy\/dx? y=cos(x+y)
解：y=coa(x+y)dy\/dx=-sin(x+y)·(1+dy\/dx)dy\/dx=-sin(x+y)-sin(x+y)·dy\/dx [1+sin(x+y)]dy\/dx=-sin(x+y)dy\/dx=-sin(x+y)\/[1+sin(x+y)]
求由下列方程确定的隐函数的导数dy\/dx (1)y=cos(x+y) 2
1)y = cos(x+y) y'= -sin(x+y) (1+y') y'+ y'sin(x+y) = -sin(x+y) y'= -sin(x+y)\/[1+sin(x+y)]2)y = x + 1\/lny^2 y'= 1 - (2yy'\/y^2)\/(lny^2)^2 y'{1+2\/y(lny^2)^2}= 1 y'= 1\/[1+2\/y(lny^2)^2]y'= 1\/[1+...
求方程所确定的隐函数y的导数dy\/dx?
dy\/dx = y(y - 4x)\/(2x² - 2xy + 3y²),8,关键：y是x的函数。(y-xy')\/y^2=1\/xy*(y+xy'xy-y^2=(x^2+xy)y'y'=y(x-y)\/[x(x+y)]4xy+2x^2y'-y^2-2xyy'+3y^2y'=0 y'=y(y-4x)\/(2x^2-2xy+3y^2),2,O客回答正确,0,求方程所确定的隐函数y...
求由方程y=1+xsiny所确定的隐函数y=y(x)的导数dy\/dx
回答：两端同时对x求导得dy\/dx=siny+x*cosy*dy\/dx解得dy\/dx=siny\/(1+xcosy)
求方程所确定的隐函数的导数dy\/dx:siny=ln(x+y)
两边微分 cosydy=(dx+dy)\/(x+y)[cosy(x+y)-1]dy=dx dy\/dx=1\/[cosy(x+y)-1]
求由方程y=sin(x+y)所确定的隐函数的导数dy\/dx
求由方程y=sin(x+y)所确定的隐函数的导数dy\/dx 我来答 1个回答 #热议# 历史上日本哪些首相被刺杀身亡?暔馗刃85 2022-06-24 · 超过82用户采纳过TA的回答 知道答主 回答量:132 采纳率:0% 帮助的人:107万 我也去答题访问个人页 关注 ...
求由方程所确定的隐函数的导数dy\/dx
xe^xydy\/dx
求由方程y=sin(x+y)所确定的隐函数的导数dy\/dx
求由方程y=sin(x+y)所确定的隐函数的导数dy\/dx 我来答 2个回答 #热议# 已婚女性就应该承担家里大部分家务吗?涂智华 2015-01-17 · 知道合伙人教育行家 涂智华 知道合伙人教育行家 采纳数:603 获赞数:1741 数学竞赛获奖选手向TA提问 私信TA 关注 ...
求方程所确定的隐函数y的导数dy\/dx
1 = (dy\/dx)lnx + y\/x + (dy\/dx)lny + dy\/dx dy\/dx = [1 - y\/x]\/[1 + ln(xy)] = y(x - y)\/x(x + y)2x²y - xy² + y³ = 0 4xy + 2x²dy\/dx - y² - 2xydy\/dx + 3y²dy\/dx = 0 dy\/dx = y(y - 4x)\/(2x&su...
