已知关于x的方程x+1/x=c=1/c的解是x1=c,x2=1/c,

Question

已知关于x的方程x+1/x=c=1/c的解是x1=c,x2=1/c,试根据此方程解的特点解关于x的方程:x+1/x-1=a+1/a-1

Answer 1

x+1/x-1=a+1/a-1变形为x-1+1/x-1=a-1+1/a-1根据方程x+1/x=c=1/c的解是x1=c,x2=1/c
x-1=a-1或x-1=1/a-1
所以x1=a,x2=1/a-1+1=a/a-1

Answer 2

x-1+1/(x-1)=a-1+1/(a-1)
x-1=a-1或x-1=1/（a-1）
x=a或x=a/(a-1)

Answer 3

x1=a,x2=1/a-1+1=a/a-1

Answer 4

x1=a,x2=1/a

Answer 5

x1=c,x2=1/c-1+1=c/c-1