=lim(x->-1)[(x²-x-2)/((x+1)(x²-x+1))]
=lim(x->-1)[((x-2)(x+1))/((x+1)(x²-x+1))]
=lim(x->-1)[(x-2)/(x²-x+1)]
=(-1-2)/(1-(-1)+1)
=-1.本回答被网友采纳
C
求极限 lim(1\/(x+1)-3\/(x^3+1))
简单分析一下，答案如图所示
求极限lim(1\/(x+1)-3\/(x^3+1)) x趋于-1
：原式=lim(x->-1)[1\/(x+1)-3\/((x+1)(x²-x+1))]=lim(x->-1)[(x²-x-2)\/((x+1)(x²-x+1))]=lim(x->-1)[((x-2)(x+1))\/((x+1)(x²-x+1))]=lim(x->-1)[(x-2)\/(x²-x+1)]=(-1-2)\/(1-(-1)+1)=-1。
求lim [(1\/x+1)-(3\/x^3+1)]= x→-1
简单分析一下，详情如图所示
当x→-1的时候1\/(x+1)-3\/(x^3+1)的极限是多少
设f(x)=1\/(x＋1)－3\/(x³＋1)=(x²－x－2)\/(x³＋1)则对f(x)分子分母分别求导，得：(2x－1)\/(3x²)，则：原来的极限=分子分母分别求导后的极限==>>>以x=－1代入== －1
...急~~ lim(1\/x+1-3\/X^3+1) x趋近-1 求函数极限
通分,分解因式,约去X+1 lim(x^2-x+1-3)\/(X^3+1)=lim(x^2-x-2)\/\/X^3+1)=lim(x-2)\/(x^2-x+1)=-1
lim(1\/x+1-3\/X^3+1) x趋近-1 求函数极限
通分,分解因式,约去X+1 lim(x^2-x+1-3)\/(X^3+1)=lim(x^2-x-2)\/\/X^3+1)=lim(x-2)\/(x^2-x+1)=-1
...急~~ lim(1\/x+1-3\/X^3+1) x趋近-1 求函数极限
通分,分解因式,约去X+1 lim(x^2-x+1-3)\/(X^3+1)=lim(x^2-x-2)\/\/X^3+1)=lim(x-2)\/(x^2-x+1)=-1
求[1\/(x+1)]-[3\/(x^3+1)]当x趋近于-1时的极限
思路如图：
高等函数:X趋向-1,求X+1分之一减去X的三次方加一分之三的极限
lim(x-->-1) 1\/(x+1)-3\/(x^3+1)=lim(x^2-x+1-3)\/(x^3+1)=lim(x^2-x-2)\/(x^3+1)=lim(2x-1)\/(3x^2)=(-2-1)\/(3)=-1
若lim[1\/(ax+1)-3∕(x^3﹢1)]﹦‐1,则常数a=()(其中x→-1)
先将分式通分,1\/(ax+1)-3∕(x^3﹢1)＝[（x^3+1)-3(ax+1)]\/[(x^3+1)(ax+1)]当x→-1时,分母[(x^3+1)(ax+1)]→0,而[（x^3+1)-3(ax+1)]\/[(x^3+1)(ax+1)]极限存在,所以当x=-1时,分子[（x^3+1)-3(ax+1)]＝0,求得a=1 ...
