...求代数式x^2-2xy-5y^2\/x^2+2xy+5y^2的值. ^2表示平方.
(x-2y)(x+y)=0 x=2y或x=-y (x^2-2xy-5y^2)\/(x^2+2xy+5y^2)=(x^2-xy-2y^2-xy-3y^2)\/(x^2-xy-2y^2+3xy+7y^2)=(-xy-3y^2)\/(3xy+7y^2)因为y≠0 原式=(-x-3y)\/(3x+7y)当x=2y时,原式=(-2y-3y)\/(6y+7y)= -5\/13 当x= - y时,原式=(y-3y)\/(-...
已知xy>0,且x^2-8y^2=2xy,求5x-2y\/x+2y
(x-2y)(x+y)=0 x=2y或x=-y (x^2-2xy-5y^2)\/(x^2+2xy+5y^2)=(x^2-xy-2y^2-xy-3y^2)\/(x^2-xy-2y^2+3xy+7y^2)=(-xy-3y^2)\/(3xy+7y^2)因为y≠0 原式=(-x-3y)\/(3x+7y)当x=2y时,原式=(-2y-3y)\/(6y+7y)= -5\/13 当x= - y时,原式=(y-3y)\/(-...
...且x不等于零,y不等于零,求代数式x平方加二xy+5 y,平方?
已知x^2一xy一2y^2=0,并且还有 xy≠0。(x一y/2)^2一(3y/2)^2=0,(x+y)(x一2y)=0。①当x=一y时,x^2+2xy+5y^2 =y^2一2y^2+5y^2=4y^2;②当x=2y时,x^2+2xy+5y^2=4y^2+4y^2+5y^2 =13y^2。
已知x⊃2;-xy-2y⊃2;=0,且x、y不等于0,求代数式x⊃2;-2xy-5y...
解:∵x²-xy-2y²=0 ∴(x+y)(x-2y)=0 ∴x=-y或x=2y ∵且x、y不等于0 ∴1、把x=-y代入式子可得:(x²+2xy-5y²)\/(x²-2xy-5y²)=(y²-2y²-5y²)\/(y²+2y²-5y²)=3 2、把x=2y代入式子可得:(...
x^2y^2-xy-2y^2=0,求x\/y
x^2-xy-2y^2=0 =x^2-2xy+xy-2y^2=0 =x(x+y)-2y(x+y)=0 =(x-2y)(x+y)=0 所以记得x=2y 或者 x=-y 所以x\/y=2 或者 x\/y=-1 望采纳!
苦思冥想不得解……
1. x^2-xy-2(y^2)=0 => (x-2y)(x+y)=0 => x=2y 或 x=-y 2. x^2-2xy-5(y^2) => x^2-xy-2y^2-xy-3y^2 => -xy-3y^2 x^2+2xy+5(y^2) => x^2-xy-2y^2+3xy+7y^2 => 3xy+7y^2 即 x^2-2xy-5(y^2)\/x^2+2xy+5(y^2)=〉 (...
已知x,y为实数,且x^2+XY+Y^2-2=0,求x^2-xy+y^2的最大值和最小值
设x^2-xy+y^2=k,联立x^2+xy+y^2=2解得:x^2+y^2=(k+2)\/2,2xy=2-k 又x^2+y^2±2xy=(x±y)^2≥0 所以(k+2)\/2±(2-k)≥0 解得2\/3≤k≤6 所以x^2-xy+y^2最大值为6,最小值为2\/3
已知x^2-xy=5,2xy+y^2=3,则代数式x^2+xy+y^2的值是——
x^2-xy=5,2xy+y^2=3 两式相加得 x^2+xy+y^2=8
求证:无论x、y取何值,代数式x^2-xy+y^2-2x+5\/2的值总为非负数
配方 x²-xy+y²-2x+5\/2 =(1\/2)(2x²-2xy+2y²-4x+5)=(1\/2)[(x²-2xy+y²)+(x²-4x+4)+y²+1]=(1\/2)[(x-y)²+(x-2)²+y²+1]∵(x-y)²≥0,(x-2)²≥0,y²≥0 ∴(x-y)&...
已知x、y为实数,求x^2+2y^2-2xy-2y+5的最小值
x^2+2y^2-2xy-2y+5=x^2-2xy+y^2+y^2-2y+1+4然后可以把原式化简为(x-y)^2+(y-1)^2+4(x-y)^2最小值只能为0,(y-1)^2的最小值也只能为0,当x=1,y=1时(x-y)^2+(y-1)^2=0得到此式的最小值,(x-y)^2+(y-1)^2+4=0+4=4...