lny=ln|x-1| +2ln|x-2|+3ln|x-3|
再等式两边对x求导
y'/y=1/(x-1) +2/(x-2)+3/(x-3)
所以
y'=y*[1/(x-1) +2/(x-2)+3/(x-3)]
代入y=(x-1)(x-2)²(x-3)³
所以
y'=(x-2)²(x-3)³ + 2(x-1)(x-2)(x-3)³+3(x-1)(x-2)²(x-3)²
利用对数求导法求y=(x-1)(x-2)²(x-3)³导数 要过程,谢谢
所以 y'=y*[1\/(x-1) +2\/(x-2)+3\/(x-3)]代入y=(x-1)(x-2)²(x-3)³所以 y'=(x-2)²(x-3)³ + 2(x-1)(x-2)(x-3)³+3(x-1)(x-2)²(x-3)²
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对数求导法求导问题?
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求y=√{[(x-1)(x-2)]\/[(x-3)(x-4)]}的导数,谢谢。
取对数即可，答案如图所示
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