(x+y)(x2-xy+y2)

如题所述

解:原式=(x+y)[(x-y)²+xy]
=(x²-y²)(x-y)+x²y+xy²
=x³-x²y-xy²+y³+x²y+xy²(-x²y-xy²+x²y+xy²抵消掉)
=x³+y³
希望对你有帮助哦~
祝学习进步哦~\(^o^)/
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第1个回答  2012-07-18
(x+y)(x^2-xy+y^2)=x^3+y^3追问

x2-xy+y2可以化简成多少

化简:(x+y)(x2-xy+y2)
化简:(x+y)(x2-xy+y2)解:原式= :(x+y)(x2-xy+y2)=x*x^2-x*xy+xy^2+x^2y-xy^2+y^3 =x^3+y^3+(1-1)x^2y+(1-1)xy^2 =x^3+y^3 这个是立方和公式 立方差公式是:x^3-y^3 =(x-y)*(x^2-xy+y^2)

(x+y)(x2-xy+y2)
解:原式=(x+y)[(x-y)²+xy]=(x²-y²)(x-y)+x²y+xy²=x³-x²y-xy²+y³+x²y+xy²(-x²y-xy²+x²y+xy²抵消掉)=x³+y³希望对你有帮助哦~祝学习进步哦~\\(^o^)\/ ...

(x+y)(x的平方-xy+y的平方) 等于多少
(x+y)(x的平方-xy+y的平方)=x^3+y^3

(x+y)(x^2-xy+y^2) 计算
原式等于:x³-y³这个是立方差公式

(x+y)(x的2次-xy+y的2次)
(x+y)(x的2次-xy+y的2次)=x^3+y^3 a的3次+8b的三次=(a+2b)(a^2+4b^2-2ab)m的5次-1=(m-1)(m^4+m^3+m^2+m+1)

(x+y)(x^2-2xy+y^2)
(x+y)(x^2-2xy+y^2)=x³-2x²y+xy²+x²y-2xy²+y³=x³-x²y-xy²+y³

因式分解 (x+y)(x^2-xy-y^2)
(x+y)(x^2-xy-y^2)=(x+y)[(x^2-xy+y^2)-2y^2]=(x+y)(x^2-xy+y^2)-(x+y)*2y^2 =x^3+y^3-2xy^2-2y^3 =x^3-2xy^2-y^3

因式分解(x-2y)(x+y)(x2-xy+y2)过程和答案
(x-2y)(x+y)(x2-xy+y2)(后面两个括号里是立方和公式)=(X-2Y)(X^3+Y^3)=X^4+XY^4-2XY^3-2Y^4 参考资料:后面两个括号里是

数学因式分解(X+Y )3-(X2-Y2)(X-Y),急求!
(X+Y )3=(x+y)(x2-xy+y2),(x2-y2)(x-y)=(x+y)(x-y)2=(x+y)(x2-2xy+y2),提取(x+y),其余的合并计算结果为xy,所以结果为xy(x+y)。

3次的平方差公式
X3-Y3=(X-Y)(X2+XY+Y2)

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