ysinx-cos(x-y)=0所确定的函数的导数dy/dx是：
y'= dy/dx = [ycosx + sin(x-y)]/[sin(x-y) - sinx]
计算过程如下：
方程两边同时求导，得到下面式子：
y'sinx+ycosx+sin(x-y) (1-y') = 0
整理可得
y'[sinx -sin(x-y)] = -ycosx - sin(x-y)
所以
y'=[ycosx + sin(x-y)]/[sin(x-y) - sinx]
扩展资料：
常用的导数公式
1、C'=0(C为常数)；
2、(Xn)'=nX(n-1) (n∈R)；
3、(sinX)'=cosX；
4、(cosX)'=-sinX；
5.(aX)'=aXIna （ln为自然对数)；
6、(logaX)'=1/(Xlna) (a>0，且a≠1)；
7、(secX)'=tanX secX；
8、(cscX)'=-cotX cscX；
y'sinx+ycosx+sin(x-y) (1-y') = 0
y'[sinx -sin(x-y)] = -ycosx - sin(x-y)
y'= dy/dx = [ycosx + sin(x-y)]/[sin(x-y) - sinx]本回答被网友采纳
dy/dx=y′=[sin(x-y)+ycosx]/[sin(x-y)-sinx]。
由方程ysinx-cos(x-y)=0所确定的函数的导数dy\/dx
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