因式分解 (1)y²-y(x+y)² (2)(x+y)²-16(x-y)² (3)(x+y)²

因式分解 (1)y²-y(x+y)² (2)(x+y)²-16(x-y)² (3)(x+y)²-14(x+y)+49 (4)16-(29+3b)² (5)x²-Xy+4/1y²

1)y²-y(x+y)² =y[√y+(x+y)][√y-(x+y)]
=y(x+y+√)(√y-x-y)
2)(x+y)²-16(x-y)² =[(x+y)+4(x-y)][(x+y)-4(x-y)]
=(5x-3y)(5y-3x)
3)(x+y)²-14(x+y)+49
=[(x+y)+7 ]²
=(x+y+7)²
4)16-(29+3b)² =[4+(29+3b][4-(29+3b]
=-3(11+b)(25-3b)
5)x²-Xy+4/1y²=(x-1/2*y)²=(2x-y)²/4
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第1个回答  2014-05-08
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我觉得你的式子有问题,我想看一下原题。

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(x-y)²-16(x+y)²=(x-y+4x+4y)(x-y-4x-4y)=-(5x+3y)(5x+5y)愿我的回答对你有帮助!如有疑问请追问,愿意解疑答惑。如果明白,并且解决了你的问题,请及时采纳为最佳答案!O(∩_∩)O

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