为什么x-y=-4xy
追答1/x-1/y=4
(y-x)/xy=4
x-y = -4xy
(5x-4xy-5y)/(x+xy-y)
=[(x-y)-4xy ]/(x-y +xy)
=-8xy/(-3xy)
=8/3
如果1\/x+1\/y=4,则代数式5x+xy+5y\/2x-xy+2y的值
解:已知x分之1+y分之1=4,得xy分之y+xy分之x=4 y+x=4xy 则(2x-xy+2y)分之(5x+xy+5y)=[(2y+2x)-xy]分之[(5y+5x)+xy]=[2×(y+x)-xy]分之[5×(y+x)+xy]=(2×4xy-xy)分之(5×4xy+xy)=(8xy-xy)分之(20xy+xy)=7xy分之21xy =3 即已知x分之1...
已知1\/x减1\/y=3,求5x+3xy-5y\/x-xy-y的值
(5x+3xy-5y)\/(x-xy-y) 分子分母同时除以xy得 =(5\/y+3-5\/x)\/(1\/y-1-1\/x)=[-5(1\/x-1\/y)+3]\/[-(1\/x-1\/y)-1]=(-5×3+3)\/(-3-1)=(-12)\/(-4)=3
已知1\/x-1\/y=5,求分式3x+5xy-3y\/x-3xy-y的值
解:1\/x-1\/y=5 (x-y)\/xy=-5 x-y=-5xy 带入后式 原式=【3(x-y)+5xy】\/【(x-y)-3xy】=(-10xy)\/(-8xy)=5\/4
已知x➗1-y➗1=3 则(5x+xy-5y)➗(x-xy-y)的值
答:解:∵(x+y-1)²≥0,√(2x-y+4)≥0,且两者互为相反数∴x+y-1=0…(1)2x-y+4=0…(2)解(1)、(2)得 x=-1,y=2 则:1\/(y^x)=-1\/[2^(-1)]=-2。 >>y 根号下1-x的平方 问:y=根号下x的平方-x+1再减去根号下x的平方+x+1,怎么由此式推出...
...已知1\/x+1\/y=2 ,求(5x+2xy+5y)\/(x-3xy+y)的值,尽量注明过程。谢谢...
1\/x+1\/y=2,通分得:(x+y)\/xy=2 也就是 x+y=2xy 所以5x+5y=10xy x+y=2xy 然后(5x+2xy+5y)\/(x-3xy+y)=(10xy+2xy)\/(2xy-3xy)=12xy\/(-xy)=-12 看看算的对吗?
已知x分之1 减y分之1等于3 求 x-xy-y 分之 5x-xy-5y等于多少
x分之1 减y分之1等于3 1\/x-1\/y=3 (y-x)\/xy=3 y-x=3xy 所以 x-xy-y 分之 5x-xy-5y =(-3xy-xy)分之(-15xy-xy)=-4分之-16 =4
谁能给我讲讲轮换因式分解啊??{高分}
=[(x+1)^2-y(x^2-1)][(x-1)^2-y(x^2-1)] =(x+1)(x+1-xy+y)(x-1)(x-1-xy-y) 2.证明:对于任何数x,y,下式的值都不会为33 x^5+3x^4y-5x^3y^2+4xy^4+12y^5 解:原式=(x^5+3x^4y)-(5x^3y^2+15x^2y^3)+(4xy^4+12y^5) =x^4(x+3y)-5x^2y^2(x+3y)+4y^...
已知1\/x-1\/y=3,求代数式2x-14xy-2y\/x-2xy-y的值
解:由1\/x-1\/y=1,变形 两边各乘以xy,得,y-x=3xy,∴xy=1\/3(y-x),(2x-14xy-2y)\/(x-2xy-y)=[2x-14\/3(y-x)-2y]\/ [ x-2\/3(y-x)-y) ],分式上下各乘以3,并展开括号,得 3(2x-14\/3y+14\/3x-2y)\/3(x-2\/3y+2\/3x-y)=(6x-14y+14x-6y)\/(3x-2y+2x-3y)...
初一数学有个叫做简便运算,解方程,合并同类项化简,合并同类项化简求值...
所以x=2 y=2 5.x=4y 3x+11-x-y=25 x=8 y=2 6.(x-2)12=8x x=6 7.x+y=4\/5.2 x-y=4\/6.5 解得:x=9\/13,y=1\/13 8.5*(1\/3)+5*X=15*X x=1\/6 9.(1\/3)x\/12=(1\/3)x\/[12*(5\/4)]+1 化简得: (5\/3)x=(4\/3)x+60 (1\/3)x=60 x=180 10.2X+5X=14000 7X=14000...
1\/4ⅹ+1\/5y=1 x-2\/2-y+4\/4=13
1\/4x+1\/5y=1……5x+4y=20……(1)x-2\/2-y+4\/4=13……x=13+y……(2)(2)代入(1):5(13+y)+4y=20 65+5y+4y=20 9y=-45 y=-5 x=13-5=8