已知x+y=4,xy=1,求x^5+y^5
解:x^2+y^2=(x+y)^2-2xy=14 x^3+y^3=(x+y)(x^2-xy+y^2)=(x+y)((x+y)^2-3xy)=4*(16-3)52 x^5+y^5=(x+y)(x^4-x^3y+x^2y^2-xy^3+y^4)=(x+y)((x^2+y^2)^2-x^2y^2-xy(x^2+y^2))=4*(14^2-1-14)=4*181 =724 ...
x+y=3,xy=1,求x^5+y^5
(x³+y³)(x²+y²)=7X18=126=x^5+y^5+x³y²+x²y³=x^5+y^5+x²y²(x+y)=+3 所以x^5+y^5=123
x十y=4,x.y=1求x5次方+y5次方=?
x5+y5=(x+y)(x4+y4-x3.y3)=4{(x2+y2)2-2x2y2-1} =4×193 =772
x+y=4 xy=2 x^5+y^5=? 急!!详细过程
解:x^2+y^2=(x+y)^2-2xy=4^2-2*2=12 x^3+y^3=(x+y)(x^2-xy+y^2)=4*(12-2)=40 所以:x^5+y^5 =(x^2+y^2)*(x^3+y^3)-x^2*y^2*(x+y)=(x^2+y^2)*(x^3+y^3)-(xy)^2*(x+y)=12*40-2^2*4 =480-16 =464 ...
已知x+y=4,xy=1求x五次方y四次方+x四次方y五次方
=(xy)的4次方(x+y)=1的4次方×4 =1×4 =4 (a-b)²-16(a+b)²=[(a-b)+4(a+b)][(a-b)-4(a+b)]=(5a+3b)(-3a-5b)=-(5a+3b)(3a+5b)x³y+xy³+2x²y²=xy(x²+2xy+y²)=xy(x+y)²=4分之3×2²=4...
若x+y=3,xy=1,则x^5+y^5=
x+y=3,xy=1 x²+y²=(x+y)²-2xy=9-2=7 x³+y³=(x+y)³-3xy(x+y)=27-9=18 所以 x^5+y^5=(x²+y²)(x³+y³)-x²y³-x³y²=(x²+y²)(x³+y...
已知x+y=4 xy=1,求x2+y2, x3+y3, x4+y4, x5+y5 x6+y6 x7+y7
x2+y2=(x+y)2-2xy=14 x3+y3=(x2+y2)×(x+y)-xy2-yx2=14×4-xy(x+y)=52 ……剩下的就是这么个算法,手机党,求个最佳哈
x+y=1 x^ +y^ =2,求x^5+y^5
(x+y)²=x²+y²+2xy=1,xy=-1\/2,(x+y)³=x³+y³+3xy(x+y)=1,x³+y³=5\/2,(x²+y²)²=4,x^4 +y^4=7\/2,(x+y)(x^4 +y^4)=x^5+y^5+xy(x³+y³),x^5+y^5-1\/2*5\/2=7\/2,x^5+y^5=19\/4 已赞过 已踩过< 你对这个回答的评价是?
已知x+y=5,xy=3,求x^5+y^5
x+y=5 两边平方 x^2+2xy+y^2=25 x^2+y^2=25-2xy=19 x^3+y^3 =(x+y)(x^2-xy+y^2)=5*(19-3)=80 (x^2+y^2)(x^3+y^3)=x^5+y^5+x^3y^2+x^2y^3 所以x^5+y^5 =(x^2+y^2)(x^3+y^3)-x^2y^2(x+y)=19*80-3^2*5 =1475 ...
解题:已知x+Y=5,xy=3,求x^5+Y^5
x^2+y^2=(x+y)^2-2xy=19 x^3+y^3=(x+y)(x^2-xy+y^2)=5*(19-3)=80 x^5+y^5 =(x^2+y^2)*(x^3+y^3)-x^2*y^2*(x+y)=19*80-9*5 =1520-45 =1475